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9x^2+54x+55=0
a = 9; b = 54; c = +55;
Δ = b2-4ac
Δ = 542-4·9·55
Δ = 936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{936}=\sqrt{36*26}=\sqrt{36}*\sqrt{26}=6\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6\sqrt{26}}{2*9}=\frac{-54-6\sqrt{26}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6\sqrt{26}}{2*9}=\frac{-54+6\sqrt{26}}{18} $
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